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36x^2+69x+30=0
a = 36; b = 69; c = +30;
Δ = b2-4ac
Δ = 692-4·36·30
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(69)-21}{2*36}=\frac{-90}{72} =-1+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(69)+21}{2*36}=\frac{-48}{72} =-2/3 $
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